Binārā meklēšana tiek izmantota, lai meklētu galveno elementu no vairākiem elementiem. Binārā meklēšana ir ātrāka nekā lineārā meklēšana.

kartēšana mašīnrakstā

Binārās meklēšanas gadījumā masīva elementiem jābūt augošā secībā. Ja jums ir nešķirots masīvs, varat kārtot masīvu, izmantojot Arrays.sort(arr) metodi.

Binārās meklēšanas piemērs Java

Apskatīsim binārās meklēšanas piemēru java.

 class BinarySearchExample{ public static void binarySearch(int arr[], int first, int last, int key){ int mid = (first + last)/2; while( first <= last ){ if ( arr[mid] system.out.println('element is not found!'); } public static void main(string args[]){ int arr[]="{10,20,30,40,50};" key="30;" binarysearch(arr,0,last,key); < pre> <span> Test it Now </span> <p>Output:</p> <pre> Element is found at index: 2 </pre> <h2>Binary Search Example in Java using Recursion</h2> <p>Let&apos;s see an example of binary search in java where we are going to search an element from an array using recursion.</p> <pre> class BinarySearchExample1{ public static int binarySearch(int arr[], int first, int last, int key){ if (last&gt;=first){ int mid = first + (last - first)/2; if (arr[mid] == key){ return mid; } if (arr[mid] &gt; key){ return binarySearch(arr, first, mid-1, key);//search in left subarray }else{ return binarySearch(arr, mid+1, last, key);//search in right subarray } } return -1; } public static void main(String args[]){ int arr[] = {10,20,30,40,50}; int key = 30; int last=arr.length-1; int result = binarySearch(arr,0,last,key); if (result == -1) System.out.println(&apos;Element is not found!&apos;); else System.out.println(&apos;Element is found at index: &apos;+result); } } </pre> <span> Test it Now </span> <p>Output:</p> <pre> Element is found at index: 2 </pre> <h2>Binary Search Example in Java using Arrays.binarySearch()</h2> <pre> import java.util.Arrays; class BinarySearchExample2{ public static void main(String args[]){ int arr[] = {10,20,30,40,50}; int key = 30; int result = Arrays.binarySearch(arr,key); if (result <0) system.out.println('element is not found!'); else found at index: '+result); } < pre> <span> Test it Now </span> <p>Output:</p> <pre> Element is found at index: 2 </pre></0)></pre></=>

Binārās meklēšanas piemērs Java, izmantojot Recursion

Apskatīsim binārās meklēšanas piemēru java, kur mēs meklēsim elementu no masīva, izmantojot rekursiju.

 class BinarySearchExample1{ public static int binarySearch(int arr[], int first, int last, int key){ if (last>=first){ int mid = first + (last - first)/2; if (arr[mid] == key){ return mid; } if (arr[mid] > key){ return binarySearch(arr, first, mid-1, key);//search in left subarray }else{ return binarySearch(arr, mid+1, last, key);//search in right subarray } } return -1; } public static void main(String args[]){ int arr[] = {10,20,30,40,50}; int key = 30; int last=arr.length-1; int result = binarySearch(arr,0,last,key); if (result == -1) System.out.println('Element is not found!'); else System.out.println('Element is found at index: '+result); } } 

Izvade:

 Element is found at index: 2 

Binārās meklēšanas piemērs Java, izmantojot Arrays.binarySearch()

 import java.util.Arrays; class BinarySearchExample2{ public static void main(String args[]){ int arr[] = {10,20,30,40,50}; int key = 30; int result = Arrays.binarySearch(arr,key); if (result <0) system.out.println(\'element is not found!\'); else found at index: \'+result); } < pre> <span> Test it Now </span> <p>Output:</p> <pre> Element is found at index: 2 </pre></0)>