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Izdrukājiet pirmos n skaitļus ar tieši diviem iestatītajiem bitiem

Dots skaitlis n vispirms izdrukā n pozitīvus veselus skaitļus ar tieši diviem kopas bitiem to binārajā attēlojumā.
Piemēri:

Input: n = 3  
Output: 3 5 6
The first 3 numbers with two set bits are 3 (0011)
5 (0101) and 6 (0110)
Input: n = 5
Output: 3 5 6 9 10 12

A Vienkāršs risinājums ir ņemt vērā visus pozitīvos veselos skaitļus pa vienam, sākot no 1. Katram skaitlim pārbaudiet, vai tajā ir tieši divas bitu kopas. Ja skaitlim ir tieši divi iestatīti biti, izdrukājiet to un palieliniet šādu skaitļu skaitu.
An Efektīvs risinājums ir tieši ģenerēt šādus skaitļus. Ja mēs skaidri novērojam skaitļus, mēs varam tos pārrakstīt, kā norādīts zemāk pow(21)+pow(20) pow(22)+pow(20) pow(22)+pow(21) pow(23)+pow(20) pow(23)+pow(21) pow(23)+pow(22) .........
Visus skaitļus var ģenerēt augošā secībā atbilstoši lielākajam no diviem bitiem. Ideja ir noteikt augstāku no diviem bitiem pa vienam. Pašreizējai augstākas kopas bitiem ņemiet vērā visus zemākos bitus un izdrukājiet izveidotos skaitļus.



C++
// C++ program to print first n numbers // with exactly two set bits #include    using namespace std; // Prints first n numbers with two set bits void printTwoSetBitNums(int n) {  // Initialize higher of two sets bits  int x = 1;  // Keep reducing n for every number  // with two set bits.  while (n > 0)  {  // Consider all lower set bits for  // current higher set bit  int y = 0;  while (y < x)  {  // Print current number  cout << (1 << x) + (1 << y) << ' ';  // If we have found n numbers  n--;  if (n == 0)  return;  // Consider next lower bit for current  // higher bit.  y++;  }  // Increment higher set bit  x++;  } } // Driver code int main() {  printTwoSetBitNums(4);  return 0; } 
Java
// Java program to print first n numbers // with exactly two set bits import java.io.*; class GFG  {  // Function to print first n numbers with two set bits  static void printTwoSetBitNums(int n)  {  // Initialize higher of two sets bits  int x = 1;    // Keep reducing n for every number  // with two set bits  while (n > 0)  {  // Consider all lower set bits for  // current higher set bit  int y = 0;  while (y < x)  {  // Print current number  System.out.print(((1 << x) + (1 << y)) +' ');    // If we have found n numbers  n--;  if (n == 0)  return;    // Consider next lower bit for current  // higher bit.  y++;  }    // Increment higher set bit  x++;  }  }    // Driver program  public static void main (String[] args)   {  int n = 4;  printTwoSetBitNums(n);  } } // This code is contributed by Pramod Kumar 
Python3
# Python3 program to print first n  # numbers with exactly two set bits  # Prints first n numbers  # with two set bits  def printTwoSetBitNums(n) : # Initialize higher of # two sets bits  x = 1 # Keep reducing n for every  # number with two set bits.  while (n > 0) : # Consider all lower set bits  # for current higher set bit  y = 0 while (y < x) : # Print current number  print((1 << x) + (1 << y) end = ' ' ) # If we have found n numbers  n -= 1 if (n == 0) : return # Consider next lower bit  # for current higher bit.  y += 1 # Increment higher set bit  x += 1 # Driver code  printTwoSetBitNums(4) # This code is contributed  # by Smitha 
C#
// C# program to print first n numbers // with exactly two set bits using System; class GFG   {    // Function to print first n  // numbers with two set bits  static void printTwoSetBitNums(int n)  {    // Initialize higher of   // two sets bits  int x = 1;    // Keep reducing n for every  // number with two set bits  while (n > 0)  {    // Consider all lower set bits   // for current higher set bit  int y = 0;  while (y < x)  {    // Print current number  Console.Write(((1 << x) +  (1 << y)) +' ');    // If we have found n numbers  n--;  if (n == 0)  return;    // Consider next lower bit   // for current higher bit.  y++;  }    // Increment higher set bit  x++;  }  }    // Driver program  public static void Main()   {  int n = 4;  printTwoSetBitNums(n);  } }   // This code is contributed by Anant Agarwal. 
JavaScript
<script> // Javascript program to print first n numbers // with exactly two set bits // Prints first n numbers with two set bits function printTwoSetBitNums(n) {  // Initialize higher of two sets bits  let x = 1;  // Keep reducing n for every number  // with two set bits.  while (n > 0)  {    // Consider all lower set bits for  // current higher set bit  let y = 0;  while (y < x)  {    // Print current number  document.write((1 << x) + (1 << y) + ' ');  // If we have found n numbers  n--;  if (n == 0)  return;  // Consider next lower bit for current  // higher bit.  y++;  }  // Increment higher set bit  x++;  } } // Driver code printTwoSetBitNums(4); // This code is contributed by Mayank Tyagi </script> 
PHP
 // PHP program to print  // first n numbers with  // exactly two set bits // Prints first n numbers  // with two set bits function printTwoSetBitNums($n) { // Initialize higher of // two sets bits $x = 1; // Keep reducing n for  // every number with  // two set bits. while ($n > 0) { // Consider all lower set  // bits for current higher  // set bit $y = 0; while ($y < $x) { // Print current number echo (1 << $x) + (1 << $y) ' '; // If we have found n numbers $n--; if ($n == 0) return; // Consider next lower  // bit for current  // higher bit. $y++; } // Increment higher set bit $x++; } } // Driver code printTwoSetBitNums(4); // This code is contributed by Ajit ?> 

Izvade:  
 

c# satur virkni
3 5 6 9  


Laika sarežģītība: O(n)

pavedienu sinhronizācija

Palīgtelpa: O(1)



2. pieeja: kamēr un pievienošanās izmantošana


Pieeja ir sākt no vesela skaitļa 3 un pārbaudīt, vai iestatīto bitu skaits tā binārajā attēlojumā ir vienāds ar 2 vai nē. Ja tajā ir precīzi 2 biti, pievienojiet to skaitļu sarakstam ar 2 bitiem, līdz sarakstā ir n elementi.

Algoritms

1. Inicializējiet tukšu sarakstu, lai saglabātu veselus skaitļus ar tieši diviem iestatītiem bitiem.
2. Inicializējiet veselu skaitļu mainīgo no i līdz 3.
3. Kamēr saraksta res garums ir mazāks par n, rīkojieties šādi:
a. Pārbaudiet, vai iestatīto bitu skaits i binārajā attēlojumā ir vienāds ar 2, izmantojot virknes metodi count().
b. Ja iestatīto bitu skaits ir vienāds ar 2, pievienojiet i sarakstam res.
c. Palieliniet i par 1.
4. Atgrieziet sarakstu res.

C++
#include    #include  using namespace std; int countSetBits(int num) {  int count = 0;  while (num > 0) {  count += num & 1;  num >>= 1;  }  return count; } vector<int> numbersWithTwoSetBits(int n) {  vector<int> res;  int i = 3;  while (res.size() < n) {  if (countSetBits(i) == 2) {  res.push_back(i);  }  i++;  }  return res; } int main() {  int n = 3;  vector<int> result = numbersWithTwoSetBits(n);  cout << 'Result: ';  for (int i = 0; i < result.size(); i++) {  cout << result[i] << ' ';  }  cout << endl;  return 0; } 
Java
// Java program for the above approach import java.util.ArrayList; import java.util.List; public class GFG {  // Function to count the number of set bits (binary 1s)  // in an integer  static int countSetBits(int num)  {  int count = 0;  while (num > 0) {  count += num & 1; // Increment count if the last  // bit is set (1)  num >>= 1; // Right shift to check the next bit  }  return count;  }  // Function to generate 'n' numbers with exactly two set  // bits in their binary representation  static List<Integer> numbersWithTwoSetBits(int n)  {  List<Integer> res = new ArrayList<>();  int i = 3; // Start from 3 as the first number with  // two set bits  while (res.size() < n) {  if (countSetBits(i)  == 2) { // Check if the number has exactly  // two set bits  res.add(  i); // Add the number to the result list  }  i++; // Move to the next number  }  return res;  }  public static void main(String[] args)  {  int n = 3; // Number of numbers with two set bits to  // generate  List<Integer> result = numbersWithTwoSetBits(  n); // Get the generated numbers  for (int num : result) {  System.out.print(  num + ' '); // Display the generated numbers  }  System.out.println();  } } // This code is contributed by Susobhan Akhuli 
Python3
def numbersWithTwoSetBits(n): res = [] i = 3 while len(res) < n: if bin(i).count('1') == 2: res.append(i) i += 1 return res n = 3 result = numbersWithTwoSetBits(n) output_string = ' '.join(str(x) for x in result) print(output_string) 
C#
using System; using System.Collections.Generic; class Program {  // Function to count the number of set bits (binary 1s) in an integer  static int CountSetBits(int num)  {  int count = 0;  while (num > 0)  {  count += num & 1; // Increment count if the last bit is set (1)  num >>= 1; // Right shift to check the next bit  }  return count;  }  // Function to generate 'n' numbers with exactly two set bits in their binary representation  static List<int> NumbersWithTwoSetBits(int n)  {  List<int> res = new List<int>();  int i = 3; // Start from 3 as the first number with two set bits  while (res.Count < n)  {  if (CountSetBits(i) == 2) // Check if the number has exactly two set bits  {  res.Add(i); // Add the number to the result list  }  i++; // Move to the next number  }  return res;  }  static void Main(string[] args)  {  int n = 3; // Number of numbers with two set bits to generate  List<int> result = NumbersWithTwoSetBits(n); // Get the generated numbers  Console.Write('Result: ');  foreach (int num in result)  {  Console.Write(num + ' '); // Display the generated numbers  }  Console.WriteLine();  } } 
JavaScript
// Javascript program for the above approach // Function to count the number of set bits (binary 1s) // in an integer function countSetBits(num) {  let count = 0;  while (num > 0) {  count += num & 1; // Increment count if the last  // bit is set (1)  num >>= 1; // Right shift to check the next bit  }  return count; } // Function to generate 'n' numbers with exactly two set // bits in their binary representation function numbersWithTwoSetBits(n) {  let res = [];  let i = 3; // Start from 3 as the first number with  // two set bits  while (res.length < n) {  if (countSetBits(i) === 2) { // Check if the number has exactly  // two set bits  res.push(i); // Add the number to the result list  }  i++; // Move to the next number  }  return res; } // Number of numbers with two set bits to generate let n = 3; // Get the generated numbers let result = numbersWithTwoSetBits(n); // Display the generated numbers console.log(result.join(' ')); // This code is contributed by Susobhan Akhuli 

Izvade
3 5 6

Laika sarežģītība: O(n log n), kur n ir veselu skaitļu skaits ar tieši diviem iestatītiem bitiem. Tas ir tāpēc, ka mēs pārbaudām iestatīto bitu skaitu katra vesela skaitļa binārajā attēlojumā, kas aizņem O(log n) laiku.



Telpas sarežģītība: O(n), kur n ir veselu skaitļu skaits ar tieši diviem iestatītiem bitiem. Tas ir tāpēc, ka mēs atmiņā saglabājam veselu skaitļu sarakstu ar diviem iestatītiem bitiem.
 

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