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Java Random nextInt() metode

Random klases metode nextInt() atgriež nākamo pseidogadījuma vienmērīgi sadalīto int vērtību no nejaušo skaitļu ģeneratora secības.

Sintakse

 public int nextInt() 

Parametri

TAS

Atdeves vērtība

Metode nextInt() atgriež nākamo pseidogadījuma int vērtību, kas iegūta no nejaušo skaitļu ģeneratora secības.

1. piemērs

 import java.util.Random; public class JavaRandomNextIntExample1 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(); System.out.println('Random Integer value : '+val); Integer val1 = random.nextInt(); System.out.println('Random Integer value : '+val1); } } 
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Izvade:

 Random Integer value : -298063488 Random Integer value : 1400961289 

Java Random nextInt() metode

Nejaušības klases metode nextInt(int n) atgriež pseidogadījuma int vērtību starp nulli (ieskaitot ) un norādīto vērtību (izņemot), kas iegūta no nejaušo skaitļu ģeneratora secības.

Sintakse

 public int nextInt(int n) 

Parametri

n : Tā ir atgriežamā nejaušā skaitļa saite. Tam jābūt pozitīvam.

Atdeves vērtība

Metode nextInt() atgriež nākamo pseidogadījuma int vērtību starp nulli un n, kas iegūta no nejaušo skaitļu ģeneratora secības.

Metieni

Metode nextInt() izmet IllegalArgumentException, ja n nav pozitīvs.

2. piemērs

 import java.util.Random; public class JavaRandomNextIntExample2 { static int j=1; public static void main(String[] args) { Random random = new Random(); for (int i=1;i<8;i++) { return the next pseudorandom integer value val="random.nextInt(i);" system.out.println(j++ +'. random intvalue : '+val+' '); } < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 1. Random intvalue : 0 2. Random intvalue : 1 3. Random intvalue : 0 4. Random intvalue : 3 5. Random intvalue : 1 6. Random intvalue : 0 7. Random intvalue : 0 </pre> <h2>Example 3</h2> <pre> import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print(&apos;Enter number of players.&apos;); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println(&apos;Enter name of &apos; + capacity + &apos; Players.&apos;); for (int i = 0; i <capacity; i++) { system.out.print(j++ + ' '); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +'. +xyz+' will have '+val+' bonus points.'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println(&apos;Random Integer value : &apos;+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread &apos;main&apos; java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;></pre></8;i++)>

3. piemērs

 import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print(&apos;Enter number of players.&apos;); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println(&apos;Enter name of &apos; + capacity + &apos; Players.&apos;); for (int i = 0; i <capacity; i++) { system.out.print(j++ + \' \'); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +\'. +xyz+\' will have \'+val+\' bonus points.\'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println(&apos;Random Integer value : &apos;+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread &apos;main&apos; java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;>

4. piemērs

 import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println(&apos;Random Integer value : &apos;+val); } } 
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Izvade:

 Exception in thread &apos;main&apos; java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) 

Piezīme. Ierobežotajai vērtībai ir jābūt pozitīvai, pretējā gadījumā tiks nodrošināts IllegalArgumentException.